A stone is thrown horizontally with velocity ‘g’ ms-1 from the top of a tower of height ‘g’ meter. The speed with which it hits the ground is (in ms-1)

final velocity =v=vxi+vyj magnitude of velocity=v=vx2+vy2 vx=u=g=horizontal componet of velocity is constant. from vy2=uy2+2gh; here uy=0 Vy=2gh  ; substitute given value ⇒Vy=2g×g substitute in v=vx2+vy2 substitute the obtained values, ⇒V=g2+2g2 ⇒V=3g