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A stone is thrown vertically upward. When the stone is at point A, its distance from a certain point O is 65 (OA=65) and the component of velocity along OA is nonzero. When it is at point B(OB= 10 m), the velocity at B is zero. When it is at point C(OC=6 m), the component of velocity of the particle along OC is zero. If the velocity of projection of the stone is v0 = 5 n ms-1, then the value of n is __________

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answer is 4.

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Detailed Solution

From figure,AC=(65)2−62=65−1=12m and CB=102−62=8m∴The maximum height attained by the ball isH=AB=12 m+8 m = 20 m∵ v2=u2−2gH Or 02=v02−2gH∴ v0=2gH=2×10×20=20ms−1=5n∴ n=4

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A stone is thrown vertically upward. When the stone is at point A, its distance from a certain point O is 65 (OA=65) and the component of velocity along OA is nonzero. When it is at point B(OB= 10 m), the velocity at B is zero. When it is at point C(OC=6 m), the component of velocity of the particle along OC is zero. If the velocity of projection of the stone is v0 = 5 n ms-1, then the value of n is __________