A stone is thrown vertically upward with a speed of 10m/s from the edge of a cliff 65m high. What will be its speed just before hitting the bottom?

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7 m/s

17 m/s

27 m/s

37 m/s

answer is D.

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Detailed Solution

Given that Initial speed u=10 m/sHeight h=65 m∴ from the equation v2=u2+2ghFinal speed v=u2+2gh=100+2×9.8×65=100+1274=1374=37m/s

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