Questions
A stone tied to the end of a string 100 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 22s, then the acceleration of the stone is
detailed solution
Correct option is A
Here, r = 100 cm = 1mFrequency, v = 1422 Hzω = 2πv = 2×227×1422 = 4 rads-1The acceleration of the stone isac = ω2r = (4)2(1) = 16ms-2Talk to our academic expert!
Similar Questions
A particle moves along a horizontal circle with constant speed. If 'a' is its acceleration and 'E' is its kinetic energy
A) a is constant B) E is constant C) a is variable D) E is variable
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