Questions
A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 sec, what is the magnitude and direction of acceleration of the stone ?
detailed solution
Correct option is B
The acceleration towards centre CAC=Ï2RThe tangential acceleration at, is given byat=dvdt=0â´ Net acceleration =Ï2Ror ac=(2Ïn)2R=4Ï2n2R=4Ï222442 (1)=Ï2m/s2 towards centre *** when a body moves with constant speed in a horizontal circle then it possesses only centri petal acceleration.Talk to our academic expert!
Similar Questions
Statement -A : The net acceleration of a particle in circular motion is always along the radius of the circle towards the centre
Statement -B : The velocity vector of a particle at a point is always along the tangent to the path of the particle at that point
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
