Q.
A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 sec, what is the magnitude and direction of acceleration of the stone ?
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a
Ï2m/s2 and direction along the tangent to the circle
b
Ï2(m/s)2 and direction along the radius towards the centre
c
Ï2/4m/s2 and direction along the radius towards the centre
d
Ï2m/s2 and direction along the radius away from the centre
answer is B.
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Detailed Solution
The acceleration towards centre CAC=Ï2RThe tangential acceleration at, is given byat=dvdt=0â´ Net acceleration =Ï2Ror ac=(2Ïn)2R=4Ï2n2R=4Ï222442 (1)=Ï2m/s2 towards centre *** when a body moves with constant speed in a horizontal circle then it possesses only centri petal acceleration.
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