Questions
A stone weighing 1 kg and sliding on ice with a velocity of 2 m/s is stopped by friction in 10 sec. The force of friction (assuming it to be constant) will be
detailed solution
Correct option is B
u = 2m/s, v = 0, t =10 seca=v−ut=0−210=−210=−15Friction force = ma = 1 x (-0.2) = -0.2 NTalk to our academic expert!
Similar Questions
A skier starts from rest at point A and slides down the hill without turning or breaking. The friction coefficient is . When he stops at point B, his horizontal displacement is s. What is the height difference between points A and B?
(The velocity of the skier is small, so that the additional pressure on the snow due to the curvature
can be neglected. Neglect also the friction of air and the dependence of on the velocity of the skier.)
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