First slide

Kinetic friction

Question

A stone weighing 1 kg and sliding on ice with a velocity of 2 m/s is stopped by friction in 10 sec. The force of friction (assuming it to be constant) will be

Moderate

A

-20 N
B

-0.2 N
C

0.2 N
D

20 N

Solution

u = 2m/s, v = 0, t =10 sec
$a = \frac{v - u}{t} = \frac{0 - 2}{10} = - \frac{2}{10} = - \frac{1}{5}$
Friction force = ma = 1 x (-0.2) = -0.2 N

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