The stopping potential as a function of frequency of incident radiation is plotted for two different photoelectric surfaces A and B. The graph shows that the work function of A is
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a
greater than that of B
b
smaller than that of B
c
same as that of B
d
such that no comparison can be done from given graph
answer is B.
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Detailed Solution
The i!intersect of the graph with v-axis gives the threshold frequency v0 .As v0 is s less for A and hencethe work-function W0=hv0 is less for A