First slide

Photo Electric Effect

Question

The stopping potential for photoelectrons emitted from a surface illuminated by light wavelength of 5893 Å is 0.36 V. Calculate the maximum kinetic energy of photoelectrons.

Moderate

A

1.746 eV
B

1.386 eV
C

2.106 eV
D

0.36 eV

Solution

We know that
${KE}_{\max} = hf - ϕ = (\frac{hc}{λ}) - ϕ$
$or ϕ = \frac{hc}{λ} - {KE}_{max}$
$Also, {KE}_{max} = {eV}_{s} = 0 .36 eV$

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