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Questions  

A straight conductor of length 2m is carrying a current of 10 A. P is a paint at a distance of 23m from end A as shown in figure. then magnetic induction at P is

a
43  μT
b
14 μT
c
143  μT
d
23 μT

detailed solution

Correct option is C

BP=μoi4πdsinθtanθ=223=13⇒θ=30o∴sinθ=12BP=10−7×1023×12T=143μT.

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