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Q.

A straight conductor of length 0.4 m is moved with a speed of 7 m/s perpendicular to the magnetic field of intensity of 0.9 Wb/m2. The induced e.m.f. across the conductor will be

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a

7.25 V

b

3.75 V

c

1.25 V

d

2.52 V

answer is D.

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Detailed Solution

e=Bvl⇒e=0.9×7×0.4=2.52 V
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