First slide

Drift of electrons and the origin of resistivity

Question

A straight conductor of uniform cross-section carries a current ‘ i ’. Let S = specific charge of an electron. The momentum of all the free electrons per unit length of the conductor due to their drift velocity only is

Easy

A

$iS$
B

$\frac{i}{S}$
C

$\sqrt{\frac{i}{S}}$
D

${(\frac{i}{S})}^{2}$

Solution

${i= neAV}_{d} S = e/m M o m e n t o f a l l f r e e e l e c t r o n s / l e n g t h P = \frac{m a s s o f a l l e l e c t r o n s x d r i f t v e l o c i t y}{l e n g t h o f c o n d u c t o r} = \frac{(nAl) {mV}_{d}}{l} = \frac{{nAeV}_{d} m}{e} = \frac{{neAV}_{d}}{e/m} = \frac{i}{S}$

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