A straight wire current element is carrying current 100 A, as shown in figure. The magnitude of magnetic field at point P which is at perpendicular distance 3 −1 m from the current element if end A and end B of the element subtend angle 300 and 600 at point P, as shown, is
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a
5 × 10−6 T
b
2.5 × 10−6 T
c
2.5 × 10−5 T
d
8 × 105 T
answer is A.
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Detailed Solution
B= μ0.i4πa sin θ1 + sin θ2 = 10−7 × 1003 −1 32 −12 = 5 × 10−6 T