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A straight wire current element is carrying current 100 A, as shown in figure. The magnitude of magnetic field at point P which is at perpendicular distance 31  m from the current element if end A and end B of the element subtend angle 300 and 600 at point P, as shown, is

a
5  ×  10−6  T
b
2.5  ×  10−6  T
c
2.5  ×  10−5  T
d
8  ×  105  T

detailed solution

Correct option is A

B=  μ0.i4πa  sin θ1 + sin θ2 =  10−7  ×  1003 −1   32  −12  =  5  × 10−6 T

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