is a straight wire having current 2I, and ABDE coplanar with PQ is the combination of wires and circular arc having current I. If BC is R2 and C is at distance R from PQ, then magnetic field at C is
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a
μ0IR13+14π outward
b
μ0I4R inward
c
μ0I4R1 +4π inward
d
μ04R13+4π outward
answer is D.
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Detailed Solution
for the part AB and DE magnetic field is zero as they are on the same line due to arc BD it is (112) th of a circle of radius R2 and for the straight conductior it is at a distance R. so total magnetic field is 112μ0I2R2 and μ02I2πR and both are outward