First slide

Motional EMF

Question

A straight wire of length L is bent into a semicircle. It is moved in a uniform magnetic field with speed v with diameter perpendicular to the field. The induced emf between the ends of the wire is

Moderate

A

$B L v$
B

$2 B L v$
C

$2 πBLv$
D

$\frac{2 BvL}{π}$

Solution

Induced emf, $e = B v l_{e} w h e r e l_{e} i s t h e e f f e c t i v e l e n g t h b e t w e e n t h e e n d s o f t h e b e n t r o d . \Rightarrow e = Bv (2 R) = \frac{2 BvL}{π}$ Here $l_{e} = 2 R = 2 (\frac{L}{π}) T h e r e f o r e e = \frac{2 v L B}{π}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App