Strain energy B stored in unit volume of a rod of diameter ‘d’, subjected to tensile force is ‘u’. Then the strain energy stored in unit volume of a rod of diameter ‘2d’, made of same material and subjected to same tensile force, will be
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a
u / 8
b
u / 16
c
2u
d
4u
answer is B.
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Detailed Solution
Stress = σ =4Fπd2 and u= σ22Y=8F2π2d4Y σ'=4Fπ2d2=Fπd2 and u'=σ'22Y=F22π2d4Y∴u'u=116⇒u'=u16