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Q.

A straw 6 cm long floats on water. The water film on one side has surface tension of 50 dyne/cm. On the other side, camphor reduces the surface tension to 40 dyne/cm. The resultant force acting on the straw is

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a

60 dyne

b

10 dyne

c

506−406 dyne

d

90 dyne

answer is A.

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Detailed Solution

F=σ1−σ2l=(50×6−40×6)=60dyne
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