First slide

Change of state

Question

Stream at $100^{0} C$ is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at $15^{0} C$ till the temperature of the calorimeter and its content rises to $80^{0} C$ . The mass of the steam condensed in kg is

Moderate

A

0.130
B

0.065
C

0.260
D

0.135

Solution

Heat is lost by steam in two stages (i) for change of state from steam at $100^{0} C$ to water at $100^{0} C$ is $m \times 540 (ii) to change in water at 100^{0} C$ to water $at 80^{0} C is m \times 1 \times (100 - 80), where m is the mass of steam condensed .$
Total heat lost by steam = $m \times 540 + m \times 20 = 560 m cal$
Heat gained by calorimeter and its contents = $(1.1 + 0.02) \times (80 - 15) = 1.12 \times 65 cal$
Using principle of calorimetry,
Heat gained = heat lost
560 m = 1.12 $\times$ 65
m = 0.130 gm

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