A stream of particles of mass m and separation d hits a perpendicular wall with a velocity v0 and rebounds along the original line of motion with a velocity v. The mass per unit length of the incident stream is λ=md. The force exerted by the stream on the wall is xλv0(v0+v)Find the x=?
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answer is 1.
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Detailed Solution
Change in momentum of one particle Δp=m(v0+v) dt=dv0;λ=md⇒F=dpdt=m(v0+v)v0d F=λ(v0+v)v0