Q.

A streamlined body falls through air from a height h on the surface of a liquid. If d and D(D > d) represents the densities of the material of the body and liquid respectively, then the time after which the body will be instantaneously at rest, is

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a

2hg

b

2hg⋅Dd

c

2hg⋅dD

d

2hgdD−d

answer is D.

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Detailed Solution

Upthrust - weight of body = apparent weight VDg−Vdg=Vdawhere a = retardation of body∴a=D−ddgThe velocity gained after fall from h height in air, v=2ghHence, time to come in rest,t=va=2gh×d(D−d)g=2hg×d(D−d)
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