A stretched string of length $$1m$$ and mass $$5$$ × $$10$$–$$4$$ kg, fixed at both ends, is under a tension of $$20$$ N. If it is plucked at points situated at $$25$$ cm from one end, it would vibrate with a frequency :

Question

A stretched string of length $$1m$$ and mass $$5$$ × $$10$$–$$4$$ kg, fixed at both ends, is under a tension of $$20$$ N. If it is plucked at points situated at $$25$$ cm from one end, it would vibrate with a frequency :

Infinity Learn · Accepted Answer

Standing waves of produced in the string attached on both the ends, whose frequency is given by  $$n2lT$$μ$$T=20Nand$$   μ$$=5$$×$$10$$−$$4$$∴$$frequency=n24$$×$$104=100$$  nNow according to question the string is plucked at $$25$$ cmThus antinode is present at $$25$$ cm, thus λ$$4=25$$ cm  λ$$=100$$ cm ∴$$n=2$$, hence frequency $$=$$ $$200Hz$$

A stretched string of length 1m and mass 5 × $10^{- 4}$ kg, fixed at both ends, is under a tension of 20 N. If it is plucked at points situated at 25 cm from one end, it would vibrate with a frequency :

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A stretched string of length 1m and mass 5 × 10–4 kg, fixed at both ends, is under a tension of 20 N. If it is plucked at points situated at 25 cm from one end, it would vibrate with a frequency :

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A stretched string of length 1m and mass 5 × $10^{- 4}$ kg, fixed at both ends, is under a tension of 20 N. If it is plucked at points situated at 25 cm from one end, it would vibrate with a frequency :