Story
NEET AITS
Story
Mock Tests
Story
Live Class
Story
JEE AITS

Questions  

A stretched string of length 1m and mass 5 × 104 kg, fixed at both ends, is under a tension of 20 N. If it is plucked at points situated at 25 cm from one end, it would vibrate with a frequency :

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
400 Hz
b
200 Hz
c
100 Hz
d
256 Hz

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is B

Standing waves of produced in the string attached on both the ends, whose frequency is given by  n2lTμT=20Nand   μ=5×10−4∴frequency=n24×104=100  nNow according to question the string is plucked at 25 cmThus antinode is present at 25 cm, thus λ4=25 cm  λ=100 cm ∴n=2, hence frequency = 200Hz

ctaimg

Similar Questions

In Melde’s experiments in the longitudinal mode of vibration a string vibrates in 4 loops with a load of 8 gm. How much load would be required in order that the string many vibrate in 8 loops in transverse mode.

Want to Improve your productivity
talk to our academic experts now !!

counselling
india
+91

whats app icon