Questions
A stretched string of length 1m and mass 5 × kg, fixed at both ends, is under a tension of 20 N. If it is plucked at points situated at 25 cm from one end, it would vibrate with a frequency :
detailed solution
Correct option is B
Standing waves of produced in the string attached on both the ends, whose frequency is given by n2lTμT=20Nand μ=5×10−4∴frequency=n24×104=100 nNow according to question the string is plucked at 25 cmThus antinode is present at 25 cm, thus λ4=25 cm λ=100 cm ∴n=2, hence frequency = 200HzSimilar Questions
In Melde’s experiments in the longitudinal mode of vibration a string vibrates in 4 loops with a load of 8 gm. How much load would be required in order that the string many vibrate in 8 loops in transverse mode.
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