Q.
A stretched string of length 2 m vibrates in 4 segments. The distance between consecutive nodes is
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a
0.5 m
b
0.25 m
c
1.0 m
d
0.75 m
answer is A.
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Detailed Solution
Given length of the string l=2 m Number of segments n=4The distance between consecutive nodes l=nλ2⇒l=4λ2⇒2=2λ⇒λ=1The distance for one segment l=λ2 =12 =0.5 m
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