First slide
Standing waves

A stretched string of 1 m length, fixed at both ends, having a mass of 5 x 10-4 kg is under a tension of 20 N. It is plucked at a point situated at 25 cm from one end. The stretched string would vibrate with a frequency of-


Here, =1m,m=5×104kg,T=20N
We have, v=12Tμ=12(1)205×104=124×104=2×1022=102=100Hz

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