A stretched string of 1 m length, fixed at both ends, having a mass of 5 x 10-4 kg is under a tension of 20 N. It is plucked at a point situated at 25 cm from one end. The stretched string would vibrate with a frequency of-

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

400 Hz

100 Hz

200 Hz

256 Hz

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Here, ℓ=1m,m=5×10−4kg,T=20NWe have, v=12ℓTμ=12(1)205×10−4=124×104=2×1022=102=100Hz

Watch 3-min video & get full concept clarity