A stretched string of 1 m length, fixed at both ends, having a mass of 5 x 10-4 kg is under a tension of 20 N. It is plucked at a point situated at 25 cm from one end. The stretched string would vibrate with a frequency of-

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400 Hz

100 Hz

200 Hz

256 Hz

answer is B.

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Detailed Solution

Here, ℓ=1m,m=5×10−4kg,T=20NWe have, v=12ℓTμ=12(1)205×10−4=124×104=2×1022=102=100Hz

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