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Q.

A stretched string of 1m length and mass 5×10−4kg is having tension of 20N. If it is plucked at 25cm from one end then it will vibrate with frequency

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a

100 Hz

b

200 Hz

c

256 Hz

d

400 Hz

answer is B.

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Detailed Solution

As we know plucking distance from one end =l2p⇒25=1002p⇒p=2. Hence frequency of vibration n=p2lTm=22×1205×10−4=200Hz.
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