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A string of length L is fixed at one end and carries a mass M at the other end. The string makes 2π revolutions per second around the vertical axis through the fixed end as shown in the figure, then tension in the string is

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a

ML

b

2 ML

c

4 ML

d

16 ML

answer is D.

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Detailed Solution

T sin θ = Mω2R-------------------(i) T sin θ = Mω2L sin θ----------(ii)From (i) and (ii)T = Mω2L = M4π2n2L = M4π2(2π)2L = 16 ML

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