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Questions  

A string of length L and force constant k is stretched to obtain extension l. It is further stretched to obtain
extension l1. The work done in second stretching is [MHT CET 2014]

a
12kl12l+l1
b
12kl12
c
12kl2+l12
d
12kl12-l2)

detailed solution

Correct option is A

Work done in stretching a string to obtain an extension I,W1=12kl2Similarly, work done is stretching a string to obtain extensionl+l1,  W2=12kl1+l2 Now, work done in second stretching,W2=W2'-W1=12kl1+l2-12kl2=12kl12l+l1

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Similar Questions

Two similar springs P and Q have spring constants Kp and KQ such that Kp > KQ. They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs WP and WQ are related as, in case (a) and case (b), respectively.


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