A string of length L and force constant k is stretched to obtain extension l. It is further stretched to obtainextension l1. The work done in second stretching is [MHT CET 2014]
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a
12kl12l+l1
b
12kl12
c
12kl2+l12
d
12kl12-l2)
answer is A.
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Detailed Solution
Work done in stretching a string to obtain an extension I,W1=12kl2Similarly, work done is stretching a string to obtain extensionl+l1, W2=12kl1+l2 Now, work done in second stretching,W2=W2'-W1=12kl1+l2-12kl2=12kl12l+l1