A string of length l $$=$$ $$1$$ m is fixed at one end and carries a mass of $$100$$ gm at other end. The string makes $$5/$$π revolution per second about a vertical axis passing through its second end. What is the angle of inclination of the string with the vertical?

Question

A string of length l $$=$$ $$1$$ m is fixed at one end and carries a mass of $$100$$ gm at other end. The string makes $$5/$$π revolution per second about a vertical axis passing through its second end. What is the angle of inclination of the string with the vertical?

Infinity Learn · Accepted Answer

The different forces are shown in figure. From figureT $$sin$$θ $$=$$ $$mv2r$$ $$=$$ mω$$2r$$ $$=$$ mω$$2lsin$$θ $$----(i)and$$ T $$cos$$ θ $$=$$ mgFrom equation (i)T=$$ mω$$2l$$ $$=$$ mω$$2$$    $$(l$$ $$=$$ $$1$$ $$m)From$$ equation $$(ii),mω$$2cos$$θ $$=$$ mgcos θ $$=$$ gω$$2$$ $$=$$ $$g4$$$$π$$$$2n2$$ $$=$$ $$104$$$$π$$$$2(5/$$π$$2)or$$ $$cos$$θ $$=$$ $$0.5$$ i.e, θ $$=$$ $$600$$

A string of length l = 1 m is fixed at one end and carries a mass of 100 gm at other end. The string makes $\sqrt{5} / π$ revolution per second about a vertical axis passing through its second end. What is the angle of inclination of the string with the vertical?

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A string of length l = 1 m is fixed at one end and carries a mass of 100 gm at other end. The string makes 5/π revolution per second about a vertical axis passing through its second end. What is the angle of inclination of the string with the vertical?

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A string of length l = 1 m is fixed at one end and carries a mass of 100 gm at other end. The string makes $\sqrt{5} / π$ revolution per second about a vertical axis passing through its second end. What is the angle of inclination of the string with the vertical?