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Q.

The string of length L is stretched by x when the speed of transverse wave along it is V1. The string is further stretched by ∆x when the speed of transverse wave along it is V12. Find ∆x:

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a

(2-1)x

b

x2

c

x

d

(2+1)x

answer is C.

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Detailed Solution

V = Tμ   ⇒ V ∝Tand stress ∝strainhence, tension ∝deformationT ∝ ∆lHence T1T2 = xx+∆x = [V1V2]2xx+∆x  = 122   ⇒2 x = (x+∆x)⇒ x= ∆x
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