The string of length L is stretched by x when the speed of transverse wave along it is V1. The string is further stretched by ∆x when the speed of transverse wave along it is V12. Find ∆x:
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a
(2-1)x
b
x2
c
x
d
(2+1)x
answer is C.
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Detailed Solution
V = Tμ ⇒ V ∝Tand stress ∝strainhence, tension ∝deformationT ∝ ∆lHence T1T2 = xx+∆x = [V1V2]2xx+∆x = 122 ⇒2 x = (x+∆x)⇒ x= ∆x