Questions
A string of length 2 m is fixed at both ends. If this string vibrates in its fourth normal mode with a frequency of 500 Hz then the waves would travel on its with a velocity of
detailed solution
Correct option is C
For string λ=2lpwhere p = No. of loops = Order of vibrationHence for forth mode p = 4 ⇒λ=l2Hence v=nλ=500×22=500 m/sTalk to our academic expert!
Similar Questions
A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)
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