Questions
A string of length and mass is fixed at both ends. The tension in the string is 8 N . The string is sent into vibration using an external vibrator of frequency 100 Hz . The separation between successive nodes on the string is close to
detailed solution
Correct option is B
Velocity of wave on string V=Tμ=85×10−3=40 m/sec Wave length of wave : λ=vf ⇒λ=40100m Separation between successive nodes =λ/2 = 20100=0.2 m =20 cmTalk to our academic expert!
Similar Questions
A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)
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