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Q.

A string 2 m  long and fixed at its ends is driven by a  240 Hz vibrator. The string vibrates in its third harmonic mode. The speed of the wave and its fundamental frequency is

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a

320 m/sec, 120Hz

b

180 m/sec, 80Hz

c

180 m/sec, 120Hz

d

320 m/sec, 80Hz

answer is D.

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Detailed Solution

For third harmonic,  f= 3v2L ⇒3V2l=240 ⇒3×V2×2=240 ⇒V=320 m/sec  Fundamental frequency =V2l=3202×2 = 80 Hz
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