A string 2 m long and fixed at its ends is driven by a 240 Hz vibrator. The string vibrates in its third harmonic mode. The speed of the wave and its fundamental frequency is

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320 m/sec, 120Hz

180 m/sec, 80Hz

180 m/sec, 120Hz

320 m/sec, 80Hz

answer is D.

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Detailed Solution

For third harmonic, f= 3v2L ⇒3V2l=240 ⇒3×V2×2=240 ⇒V=320 m/sec Fundamental frequency =V2l=3202×2 = 80 Hz

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