The string of a simple pendulum is replaced by a uniform rod of length L and mass M while the bob has a mass m. It is allowed to make small oscillations. Its time period is
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a
2π2M3mLg
b
2π2(M+3m)L3(M+2m)g
c
2πM+mM+3mLg
d
2π2m+M3(M+2m)Lg
answer is B.
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Detailed Solution
When the rod is replaced by the string the simple pendulum will act as compound pendulum for which time period is given byT=2πI0Mgd ………(i)I0= moment of inertia about point of suspension=ML23+mL2=(M+3m)L23M' = total mass = (M + m)d = separation between point of suspension and centre of mass of the pendulum=M(L/2)+m(L)(M+m)=(M+2m)L2(M+m)Substituting the values in Eq. (i), we get⇒ T=2π2(M+3m)L3(M+2m)g