A string vibrates according to the equation y=5sin 2πx3 cos 20 πt, where x and y are in cm and t in sec. The distance between two adjacent nodes is

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3 cm

4.5 cm

6 cm

1.5 cm

answer is D.

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Detailed Solution

y=5sin 2πx3cos20 π t, comparing with equation y=2asin2πxλcos2πvtλ⇒λ=3, distance between two adjacent nodes =λ/2=1.5cm.

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