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Q.

A string is wrapped around the rim of a wheel of moment of inertia 0.20 kg m2 and of radius 20 cm. The wheel is free to rotate about its axis and initially it is at rest. The, string is now pulled by a force of 20 N. The angular velocity of the string after 5 s will be

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a

90rads−1

b

70 rad s−1

c

95rads−1

d

100rads−1

answer is D.

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Detailed Solution

We know that τ=1α…(i) and τ=rF=20100(20)τ=4NmNow from eq. (i)4 = (0.2) (α)So α=20rads−2So from ω=ω0+αtω0=0 and t=5 sec. So ω=0+20(5)ω=100rad/sec.
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A string is wrapped around the rim of a wheel of moment of inertia 0.20 kg m2 and of radius 20 cm. The wheel is free to rotate about its axis and initially it is at rest. The, string is now pulled by a force of 20 N. The angular velocity of the string after 5 s will be