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A string is wrapped on a wheel of moment of inertia 0.20 kg m2 and radius 10 cm and goes through a light pulley to support a block of mass 2.0 kg as shown in figure. Find the acceleration of the block. (in m/s2)

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answer is 00000.89.

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Detailed Solution

2g−T=2a …(i)TR=lα …(ii)a=Rα …(iii)From (ii) and (iii) T=laR2∴ 2g=a2+1R2⇒ a=2g2+1R2=2×9.82+0.20.01=9.811≈0.89m/s2

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A string is wrapped on a wheel of moment of inertia 0.20 kg m2 and radius 10 cm and goes through a light pulley to support a block of mass 2.0 kg as shown in figure. Find the acceleration of the block. (in m/s2)