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Q.

A student can distinctly see the object upto a distance 15 cm. He wants to see the black board at a distance of 3 m. Focal length and power of lens used respectively will be

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a

- 4.8 cm, - 3.3 D

b

- 5.8 cm, - 4.3 D

c

- 7.5 cm, - 6.3 D

d

- 15.8 cm, - 6.3 D

answer is D.

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Detailed Solution

v=−15cm,u=−300cm  From lens formula 1f=1v−1u ⇒1f=1−15−1−300=−19300⇒f=−30019=−15.8cm  and power P=100fcm=−100×19300=−6.33D.
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