Questions
A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is
detailed solution
Correct option is D
Diameter of the ball= MSR + CSR x (Least count) - Zero error= 5 mm + 25 x 0.001 cm - (-0.004) cm= 0.5 cm + 25 x 0.001 cm - (-0.004) cm = 0.529 cm.Talk to our academic expert!
Similar Questions
The distance moved by the screw of a screw gauge is in four rotations and there are 50 divisions on its cap. When nothing is put between its jaws, 20th division of circular scale coincides with reference line and zero of linear scale is hidden from circular scale when two jaws touch each other or zero of circular scale is lying above the reference line. When plate is placed between the jaws, main scale reads 2 divisions and circular scale reads 20 divisions. Thickness of plate is
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