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Q.

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is

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a

0.521 cm

b

0.525 cm

c

0.053 cm

d

0.529 cm

answer is D.

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Detailed Solution

Diameter of the ball= MSR + CSR x (Least count) - Zero error= 5 mm + 25 x 0.001 cm - (-0.004) cm= 0.5 cm + 25 x 0.001 cm - (-0.004) cm = 0.529 cm.
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