First slide

Screw Guage

Question

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm the correct diameter of the ball is

Easy

A

0.521 cm
B

0.525 cm
C

0.053 cm
D

0.529 cm

Solution

Diameter of the ball
$= M S R + C S R \times (Least count) - Zero error$
$\begin{array}{l} = 5 mm + 25 \times 0.001 cm - (- 0.004) cm \\ = 0.5 cm + 25 \times 0.001 cm - (- 0.004) cm = 0.529 cm . \end{array}$

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