A student measured the diameter of a small steel ball using a screw gauge of least count $$0.001$$ cm. The main scale reading is $$5$$ mm and zero of circular scale division coincides with $$25$$ divisions above the reference level. If screw gauge has a zero error of $$-0.004$$ cm the correct diameter of the ball is

Question

Infinity Learn · Accepted Answer

Diameter of the $$ball=MSR+CSR$$×$$($$ Least count $$)-$$ Zero error $$=5$$ $$mm+25$$×$$0.001$$ $$cm-(-0.004)cm=0.5$$ $$cm+25$$×$$0.001$$ $$cm-(-0.004)cm=0.529$$ cm.

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