Screw Guage

Question

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 *cm*. The main scale reading is 5 *mm* and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 *cm *the correct diameter of the ball is

Easy

Solution

Diameter of the ball

$=MSR+CSR\times \left(\text{Least count}\right)-\text{Zero error}$

$\begin{array}{l}=5\mathrm{mm}+25\times 0.001\mathrm{cm}-(-0.004)\mathrm{cm}\\ =0.5\mathrm{cm}+25\times 0.001\mathrm{cm}-(-0.004)\mathrm{cm}=0.529\mathrm{cm}.\end{array}$

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