Q.

A student is standing at a distance of 50 metres from a bus. As soon as the bus begins its motion (starts moving away from student) with an acceleration of 1 ms-2, the student starts running towards the bus with a uniform velocity u. Assuming the motion to be along a straight road. the minimum value of u, so that the student is able to catch the bus is:

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a

5ms−1

b

8ms−1

c

10ms−1

d

12ms−1

answer is C.

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Detailed Solution

50+x=ut     .......(i) and x=t22   ......(ii)From (1) and (2),50+t22=ut⇒t2−2ut+100=0For real roots, discriminant = 0For minimum velocity, discriminant = 0⇒4u2−400=0⇒u=10m/s
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