First slide

Position Path Length (Distance) And Displacement

Question

A student starts from his house with a speed 2kmph and reaches his college 3 min late. Next day he increases his speed by 1kmph and reaches college 3 min earlier. The distance between his house and college is

Moderate

A

0.6 km
B

1.6 km
C

3 km
D

2 km

Solution

$\frac{s}{2} = t + \frac{3}{60} \frac{s}{3} = t - \frac{3}{60}; \frac{s}{2} - \frac{s}{3} = \frac{6}{60} \frac{s}{6} = \frac{6}{60} \Rightarrow S = 0.6 k m$

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