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Q.

A student starts from his house with a speed 2kmph and reaches his college 3 min late. Next day he increases his speed by 1kmph and reaches college 3 min earlier. The distance between his house and college is

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a

0.6 km

b

1.6 km

c

3 km

d

2 km

answer is A.

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Detailed Solution

s2= t + 360 s3=t - 360; s2-s3= 660 s6=660⇒S=0.6km
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A student starts from his house with a speed 2kmph and reaches his college 3 min late. Next day he increases his speed by 1kmph and reaches college 3 min earlier. The distance between his house and college is