The sum of magnitudes of two forces acting at a point is 16 N. If their resultant is normal to the smaller force and has a magnitude of 8 N, then the force are
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a
6 N and 10 N
b
8 N and 8 N
c
4N and12N
d
2N and 14N
answer is A.
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Detailed Solution
See figureGiven P+Q=16N ...(1)Here R is normal to P, i.e.,R2 = Q2 -P2 =(Q -P)(Q+P)or (8)2 = (Q - P) (16)∴Q−P=4....(2)From eqs. (1) and (2)P=6N and Q=10N