Q.
The sum of the magnitudes of two forces acting at a point is 16 N. The resultant of these forces is perpendicular to the smaller force and has a magnitude of 8 N. If the smaller force is of magnitude x, then the value of x is
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a
2 N
b
4 N
c
6 N
d
7 N
answer is C.
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Detailed Solution
x+y=16. Also, y2=82+x2or y2=64+(16−y)2 [∵x=16−y]or y2=64+256+y2−32yor 32y=320 or y=10Nor x+10=16 or x=6N
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