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Q.

The sum of the magnitudes of two forces acting at a point is 16 N. The resultant of these forces is perpendicular to the smaller force and has a magnitude of 8 N. If the smaller force is of magnitude x, then the value of x is

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a

2 N

b

4 N

c

6 N

d

7 N

answer is C.

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Detailed Solution

x+y=16. Also, y2=82+x2or  y2=64+(16−y)2 [∵x=16−y]or  y2=64+256+y2−32yor  32y=320 or y=10Nor  x+10=16 or  x=6N
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The sum of the magnitudes of two forces acting at a point is 16 N. The resultant of these forces is perpendicular to the smaller force and has a magnitude of 8 N. If the smaller force is of magnitude x, then the value of x is