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Q.

The sum of the magnitudes of two forces acting at a point is 16 N. The resultant of these forces is perpendicular to the smaller force and has a magnitude of 8 N. If the smaller force is of magnitude x, then the value of x is

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a

2N

b

4N

c

6N

d

7N

answer is C.

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Detailed Solution

x + y =16.           Also, y2= 82+ x2           or       y2= 64 + 16 − y2     [ x = 16 − y] or       y2= 64 + 256 +y2− 32y           or       32y = 320      or       y = 10 N           ⇒   x + 10 = 16 or x = 6N
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