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The sum of magnitudes of two forces is $16 N$ . If their resultant is normal to the smaller force and has a magnitude of $8 N$ , then two forces are

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6 N,10 N

8 N,8 N

4 N,12 N

2 N,14 N

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detailed solution

Correct option is A

A+B=16Bsinθ=AAnd Bcosθ=8Squaring and adding these two equations, we getB2=A2+64A=6 N and B=10 N

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The sum of magnitudes of two forces is 16 N. If their resultant is normal to the smaller force and has a magnitude of 8 N, then two forces are

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The sum of magnitudes of two forces is $16 N$ . If their resultant is normal to the smaller force and has a magnitude of $8 N$ , then two forces are