The sum of two forces acting at a point is 16 N. If the resultant force is 8 N and its direction is perpendicular to minimum force then the forces are

A+B = 16(given) ……..(i)tanα = BsinθA+Bcosθ = tan900∴ A+Bcosθ = 0  ⇒  cosθ = -AB ……(ii)8 = A2+B2+2ABcos θ  ……..(iii)By solving eqs. (i), (ii) and (iii) we getA = 6 N, B = 10 N