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Q.

The sun radiates electromagnetic energy at the rate of 12.56×1025 W. Its radius is 6.96×108m. If the distance from the sun to the earth is 1.5×1011m. Then the  intensity of  sun light on earth’s surface will be ------ in  Wm2

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a

4.4×103

b

4.4×104

c

4.4×106

d

4.4×102

answer is D.

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Detailed Solution

I=P4πr2 Here P= power of radiating source     r=distance of point from source    I= intensity of electromagnetic wave  ⇒I=P4πr2=12.56×10254×3.14×2.25×1022=49×103=0.44×103=4.4×102Wm2
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