First slide

Trignometry

Question

Sun rays cast 16 m long shadow of a pole, when Sun is 37° above the horizontal. When Sun rises to 53° above the horizontal, length of shadow becomes

Moderate

A

8m
B

16m
C

9 m
D

4m

Solution

$\frac{h}{x} = \tan 53 ° = \frac{4}{3} and \frac{h}{16} = \tan 37 ° = \frac{3}{4}$
$\Rightarrow \frac{16}{x} = \frac{16}{9}$
⇒ x = 9m

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