Suppose ge be the acceleration due to gravity at the equator and gp be that at the poles' Assuming earth to be a sphere of radius Re rotating about its own axis with angular speed ω the gp, - ge, is given by
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a
ω2Re
b
Re ω2
c
ω2 R2e
d
ω2/Re2
answer is B.
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Detailed Solution
g′=g−Reω2cos2λHere g p=g because λ=90∘at Polesand ge = g - Re ω2 becauseλ=0∘.So, gp−ge=g−g+Reω2=Reω2