Question

Suppose the gravitational attraction varies inversely as the distance from the earth. The orbital velocity of a satellite in such a case varies as nth power of distance, where n is equal to

Easy

Solution

$F = \frac{k}{r}$ (where, k = constant)
$∴ \frac{m v^{2}}{r} = \frac{k}{r} o r v \propto r^{0} \Rightarrow n = 0$

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