Questions
Suppose ideal gas equation follows constant. Initial temperature and volume of the gas are T and V respectively. If gas expand to 27V then its temperature will become
detailed solution
Correct option is B
VP3 = constant = k ⇒ P = kV13Also PV = μRT ⇒ P = kV13.V = μRT ⇒ V23 = μRTkHence (V1V2)23 = T1T2 ⇒ (V27V)23 = TT2⇒ T2 = 9TTalk to our academic expert!
Similar Questions
For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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