Suppose that intensity of a laser is 315πW/m2. The rms electric field, in units of V/m associated with this source is close to the nearest integer is ε0=8.86×10−12 C2Nm−2; c=3×108 ms−1

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answer is 0194.42.

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Detailed Solution

I=12ε0E02c⇒I=ε0Erms2c⇒315π=ε0Erms23×108⇒105×10−8πε0=Erms2⇒Erms2=4×105×10−8×9×109=36×105×10⇒Erms=36×1050=6×32.4=194.42 V/m

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